20m^-6n^4/(2m^-1n^-2)^5

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Solution for 20m^-6n^4/(2m^-1n^-2)^5 equation: 


D( x )

(2*m^-1*n^-2)^5 = 0

(2*m^-1*n^-2)^5 = 0

(2*m^-1*n^-2)^5 = 0

32*m^-5*n^-10 = 0

x należy do R

x belongs to the empty set

(20*m^-6*n^4)/((2*m^-1*n^-2)^5) = 0

x belongs to the empty set

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